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Rohit borrows ₹ 400 at the rate of 5% per annum simple interest and Abhishek borrows ₹ X at the rate of 4% per annum simple interest. After 15 years their amount of debt. becomes equal. Find X.₹ 420.70₹ 437.50₹ 445.50₹ 450

Question

Rohit borrows ₹ 400 at the rate of 5% per annum simple interest and Abhishek borrows ₹ X at the rate of 4% per annum simple interest. After 15 years their amount of debt. becomes equal. Find X.₹ 420.70₹ 437.50₹ 445.50₹ 450

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Solution

The problem states that Rohit and Abhishek have the same debt amount after 15 years. We know that the formula for simple interest is I = PRT/100, where P is the principal amount, R is the rate of interest, and T is the time in years.

For Rohit, we know that P = ₹400, R = 5% per annum, and T = 15 years. So, we can calculate his interest as follows:

I = (400 * 5 * 15) / 100 = ₹300

So, after 15 years, Rohit's total debt (principal + interest) is ₹400 + ₹300 = ₹700.

For Abhishek, we know that his total debt after 15 years is also ₹700. His rate of interest is 4% per annum. Let's denote his principal amount as X. His interest after 15 years can be calculated as follows:

I = (X * 4 * 15) / 100

His total debt (principal + interest) is X + I = ₹700.

Substituting I in the equation, we get:

X + (X * 4 * 15) / 100 = ₹700 X (1 + (4 * 15) / 100) = ₹700 X * 1.6 = ₹700 X = ₹700 / 1.6 X = ₹437.50

So, Abhishek borrowed ₹437.50.

This problem has been solved

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