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Consider the gas-phase reaction below.2 H2S(g) + CH4(g) → 4 H2(g) + CS2(g)Which expression can be used to calculate the heat of reaction (ΔH°rxn) for the reaction shown using bond enthalpies (ΔH°bond)?A.ΔH°rxn=(2×ΔH°S—H)+ΔH°C—H−(4×ΔH°H—H)−ΔH°C=S∆𝐻°rxn=2×∆𝐻°S―H+∆𝐻°C―H-4×∆𝐻°H―H-∆𝐻°C=SB.ΔH°rxn=(4×ΔH°S—H)+(4×ΔH°C—H)−(4×ΔH°H—H)−(2×ΔH°C=S)∆𝐻°rxn=4×∆𝐻°S―H+4×∆𝐻°C―H-4×∆𝐻°H―H-2×∆𝐻°C=SC.ΔH°rxn=(4×ΔH°H—H)+(2×ΔH°C=S)−(4×ΔH°S—H)−(4×ΔH°C—H)∆𝐻°rxn=4×∆𝐻°H―H+2×∆𝐻°C=S-4×∆𝐻°S―H-4×∆𝐻°C―HD.ΔH°rxn=(4×ΔH°H—H)+(2×ΔH°C=S)+(4×ΔH°S—H)+(4×ΔH°C—H)∆𝐻°rxn=4×∆𝐻°H―H+2×∆𝐻°C=S+4×∆𝐻°S―H+4×∆𝐻°C―HSubmit

Question

Consider the gas-phase reaction below.2 H2S(g) + CH4(g) → 4 H2(g) + CS2(g)Which expression can be used to calculate the heat of reaction (ΔH°rxn) for the reaction shown using bond enthalpies (ΔH°bond)?A.ΔH°rxn=(2×ΔH°S—H)+ΔH°C—H−(4×ΔH°H—H)−ΔH°C=S∆𝐻°rxn=2×∆𝐻°S―H+∆𝐻°C―H-4×∆𝐻°H―H-∆𝐻°C=SB.ΔH°rxn=(4×ΔH°S—H)+(4×ΔH°C—H)−(4×ΔH°H—H)−(2×ΔH°C=S)∆𝐻°rxn=4×∆𝐻°S―H+4×∆𝐻°C―H-4×∆𝐻°H―H-2×∆𝐻°C=SC.ΔH°rxn=(4×ΔH°H—H)+(2×ΔH°C=S)−(4×ΔH°S—H)−(4×ΔH°C—H)∆𝐻°rxn=4×∆𝐻°H―H+2×∆𝐻°C=S-4×∆𝐻°S―H-4×∆𝐻°C―HD.ΔH°rxn=(4×ΔH°H—H)+(2×ΔH°C=S)+(4×ΔH°S—H)+(4×ΔH°C—H)∆𝐻°rxn=4×∆𝐻°H―H+2×∆𝐻°C=S+4×∆𝐻°S―H+4×∆𝐻°C―HSubmit

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Solution

The heat of reaction (ΔH°rxn) can be calculated using bond enthalpies (ΔH°bond) by subtracting the sum of the bond enthalpies of the reactants from the sum of the bond enthalpies of the products.

For the given reaction, the reactants are 2 H2S and 1 CH4, and the products are 4 H2 and 1 CS2.

The bond enthalpies involved in the reactants are the S-H bond in H2S and the C-H bond in CH4. The bond enthalpies involved in the products are the H-H bond in H2 and the C=S bond in CS2.

Therefore, the correct expression for calculating ΔH°rxn using bond enthalpies is:

ΔH°rxn = (4×ΔH°H—H + ΔH°C=S) - (2×ΔH°S—H + ΔH°C—H)

So, the correct answer is C. ΔH°rxn = (4×ΔH°H—H + 2×ΔH°C=S) - (4×ΔH°S—H + ΔH°C—H)

This problem has been solved

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