How many memory reads are required to read a word of the given width in each of thefollowing circumstances. (If more than one answer is possible depending on the alignment,then give the best-case and the worst-case.)(a) 4 byte word, 8-bit data bus, natural alignment required
Question
How many memory reads are required to read a word of the given width in each of thefollowing circumstances. (If more than one answer is possible depending on the alignment,then give the best-case and the worst-case.)(a) 4 byte word, 8-bit data bus, natural alignment required
Solution
In the given scenario, we have a 4-byte word and an 8-bit data bus.
1 byte = 8 bits
So, a 4-byte word = 4 * 8 = 32 bits
Given that the data bus is 8 bits wide, it can read 8 bits at a time.
To read a 32-bit word, the data bus would need to perform 4 reads.
So, in both the best-case and worst-case scenarios, 4 memory reads are required to read a 4-byte word with an 8-bit data bus, assuming natural alignment is required.
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