W = ((AB)’ + CD)’ + (ACD’)’
Solution
Sure, I can help with that. The expression you've given is a Boolean algebra expression. Here's how you can simplify it step by step:
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Apply De Morgan's law to the first part of the expression ((AB)’ + CD)’. De Morgan's law states that the complement of the sum of two variables is equal to the product of their complements. So, ((AB)’ + CD)’ becomes (A' + B') * (C' + D').
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Apply De Morgan's law to the second part of the expression (ACD’)’. This becomes A' + C' + D.
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Now, combine the two parts of the expression: (A' + B') * (C' + D') + A' + C' + D.
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Distribute the terms: A'C' + A'D' + B'C' + B'D' + A' + C' + D.
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Now, simplify the expression by combining like terms: A'C' + A'D' + B'C' + B'D' + A' + C' + D.
This is the simplified form of the given Boolean algebra expression.
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