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Consider the code below. What is the output?public class TernaryOperator { public static void main(String[] args) { int x = 30; int y = 50; String result = (x > y) ? "x is greater" : "y is greater"; System.out.println(result); }}a)"x > y"b)"y is greater"c)Compilation errord)"x is greater"

Question

Consider the code below. What is the output?public class TernaryOperator { public static void main(String[] args) { int x = 30; int y = 50; String result = (x > y) ? "x is greater" : "y is greater"; System.out.println(result); }}a)"x > y"b)"y is greater"c)Compilation errord)"x is greater"

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Solution

The output of the code will be "y is greater".

Here's the step by step explanation:

  1. The code declares a class named TernaryOperator.

  2. Inside the TernaryOperator class, it defines the main method, which is the entry point for any Java program.

  3. Inside the main method, it declares two integer variables x and y, and assigns them the values 30 and 50 respectively.

  4. Then it declares a String variable result. The value of result is determined by a ternary operation (x > y) ? "x is greater" : "y is greater".

  5. The ternary operator works like a short form of if-else statement. It first evaluates the condition x > y. If the condition is true, it assigns the string "x is greater" to result. If the condition is false, it assigns the string "y is greater" to result.

  6. Since x (which is 30) is not greater than y (which is 50), the condition x > y is false. Therefore, the string "y is greater" is assigned to result.

  7. Finally, it prints out the value of result, which is "y is greater".

So, the correct answer is b) "y is greater".

This problem has been solved

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