Knowee
Questions
Features
Study Tools

The matrixC=⎡⎣⎢(−6,2,-6),(-5,1,-6),(4,-1,5)⎤⎦⎥has two distinct eigenvalues such that λ1<λ2.The smaller eigenvalue λ1= has algebraic multiplicity and geometric multiplicity .The larger eigenvalue λ2= has algebraic multiplicity and geometric multiplicity .Is the matrix C diagonalisable? choose

Question

The matrixC=⎡⎣⎢(−6,2,-6),(-5,1,-6),(4,-1,5)⎤⎦⎥has two distinct eigenvalues such that λ1<λ2.The smaller eigenvalue λ1= has algebraic multiplicity and geometric multiplicity .The larger eigenvalue λ2= has algebraic multiplicity and geometric multiplicity .Is the matrix C diagonalisable? choose

🧐 Not the exact question you are looking for?Go ask a question

Solution

To answer this question, we first need to find the eigenvalues of the matrix C. The eigenvalues are the roots of the characteristic polynomial, which is found by subtracting λ from the diagonal entries of the matrix and then taking the determinant.

The matrix C is:

C = [ -6 2 -6 -5 1 -6 4 -1 5]

The characteristic polynomial is found by calculating the determinant of (C - λI), where I is the identity matrix and λ is a scalar. This gives us:

det(C - λI) = det([ -6-λ 2 -6 -5 1-λ -6 4 -1 5-λ])

Solving this equation will give us the eigenvalues of the matrix.

The algebraic multiplicity of an eigenvalue is the number of times it appears as a root of the characteristic polynomial. The geometric multiplicity of an eigenvalue is the dimension of the associated eigenspace.

A matrix is diagonalizable if and only if the algebraic multiplicity of each of its eigenvalues equals its geometric multiplicity.

Without the specific values of the eigenvalues and their multiplicities, we cannot determine if the matrix C is diagonalizable.

This problem has been solved

Similar Questions

The matrix A𝐴 has eigenvalues −5−5, −1−1, and 22 with corresponding eigenvectors ⎡⎣⎢07−6⎤⎦⎥[07−6], ⎡⎣⎢−13−1⎤⎦⎥[−13−1] and ⎡⎣⎢−764⎤⎦⎥[−764].  Which of the following is a valid diagonalisation?  Select all that apply.This matrix cannot be diagonalisedA=V−1DV𝐴=𝑉−1𝐷𝑉 with V=𝑉= ⎡⎣⎢07−6−13−1−764⎤⎦⎥[0−1−7736−6−14] and D=𝐷= ⎡⎣⎢−5000−10002⎤⎦⎥[−5000−10002]A=V−1DV𝐴=𝑉−1𝐷𝑉 with V=𝑉= ⎡⎣⎢0−1−7736−6−14⎤⎦⎥[07−6−13−1−764] and D=𝐷= ⎡⎣⎢−5000−10002⎤⎦⎥[−5000−10002]A=VDV−1𝐴=𝑉𝐷𝑉−1 with V=𝑉= ⎡⎣⎢0−1−7736−6−14⎤⎦⎥[07−6−13−1−764] and D=𝐷= ⎡⎣⎢−5000−10002⎤⎦⎥[−5000−10002]A=VDV−1𝐴=𝑉𝐷𝑉−1 with V=𝑉= ⎡⎣⎢07−6−13−1−764⎤⎦⎥[0−1−7736−6−14] and D=𝐷= ⎡⎣⎢−5000−10002⎤⎦⎥

Determine whether or not the 5x5 matrix 𝐴=(3 0 -5 -6 2/ 6 2 -12 -9 3/ 6 0 -10 -9 3/ -5 0 7 5 -1/ 1 0 -5 -6 4) is diagonalizable. You may use the fact that the characteristic polynomial is 𝑐𝐴(𝑡)=(𝑡−2)^3(𝑡+1)^2.

The characteristic polynomial of a 3×33×3 matrix can be factorised as (2−λ)2(5−λ)(2−𝜆)2(5−𝜆). Which of the following statements are true? Select all that apply.The geometric multiplicity of the eigenvalue λ=𝜆= 55 could be 22The number of linearly independent eigenvectors for the eigenvalue λ=𝜆= 55 must be 11The geometric multiplicity of the matrix cannot be greater than 22The geometric multiplicity of the eigenvalue λ=𝜆= 22 could be 22The algebraic multiplicity of the matrix is 22The algebraic multiplicity of the eigenvalue λ=𝜆= 22 cannot be determined from the information we are givenThe eigenvalue λ=𝜆= 22 could have infinitely many eigenvector directionsThe algebraic multiplicity of the eigenvalue λ=𝜆= 22 is 2

diagonalizing a matrix;

Consider the following matrix.A = 23 12 −36 −19Find the eigenvalues and associated eigenvectors of A. (Arrange the eigenvalues so that 𝜆1 < 𝜆2.)𝜆1 =        with eigenvector    x1 = 𝜆2 =        with eigenvector    x2 =

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.