d) The brakes applied to a car moving with a velocity of 10 m/s come to halt in 2s. Calculate the distance it travels after the brakes are applied till it stops
Question
d) The brakes applied to a car moving with a velocity of 10 m/s come to halt in 2s. Calculate the distance it travels after the brakes are applied till it stops
Solution
To solve this problem, we need to use the equations of motion.
Step 1: Identify the given values. Initial velocity (u) = 10 m/s Final velocity (v) = 0 m/s (since the car comes to a halt) Time (t) = 2s
Step 2: Use the first equation of motion to find the acceleration. The first equation of motion is v = u + at. We can rearrange this to solve for acceleration (a): a = (v - u) / t
Substitute the given values into the equation: a = (0 - 10) / 2 = -5 m/s². The negative sign indicates that this is a deceleration, as expected since the car is slowing down.
Step 3: Use the second equation of motion to find the distance travelled. The second equation of motion is s = ut + 0.5at².
Substitute the given values into the equation: s = 102 + 0.5(-5)*(2)² = 20 - 10 = 10 meters.
So, the car travels 10 meters after the brakes are applied until it stops.
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