Inlet X is 5 times faster than the outlet Y. If Y can empty a cistern in 36 minutes, the find the time when the cistern will be full if both fill pipes are opened together
Question
Inlet X is 5 times faster than the outlet Y. If Y can empty a cistern in 36 minutes, the find the time when the cistern will be full if both fill pipes are opened together
Solution
Let's solve the problem step by step:
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Let's assume that the rate at which outlet Y empties the cistern is 1 unit per minute. This means that Y can empty the cistern in 36 minutes.
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Since inlet X is 5 times faster than outlet Y, the rate at which inlet X fills the cistern is 5 units per minute.
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Now, if both inlet X and outlet Y are opened together, the net rate at which the cistern is being filled is (5 - 1) = 4 units per minute.
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To find the time it takes to fill the cistern, we need to determine how many units the cistern can hold. Let's assume the cistern can hold C units.
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The time it takes to fill the cistern can be calculated using the formula: Time = Capacity / Rate.
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Substituting the values, we have: Time = C / 4.
Therefore, the time it takes to fill the cistern when both inlet X and outlet Y are opened together is C / 4 minutes.
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