Given a linked list with string data, check whether the combined string formed is palindrome. If the combined string is palindrome then return true otherwise return false.Example:Input:Output : trueExplanation: As string "abcddcba" is palindrome the function should return true.Input:Output : falseExplanation: As string "abcdba" is not palindrome the function should return false.Expected Time Complexity: O(n)Expected Auxiliary Space: O(n)Constraints:1 <= Node.data.length<= 1031<=list.length<=103
Question
Given a linked list with string data, check whether the combined string formed is palindrome. If the combined string is palindrome then return true otherwise return false.Example:Input:Output : trueExplanation: As string "abcddcba" is palindrome the function should return true.Input:Output : falseExplanation: As string "abcdba" is not palindrome the function should return false.Expected Time Complexity: O(n)Expected Auxiliary Space: O(n)Constraints:1 <= Node.data.length<= 1031<=list.length<=103
Solution
Here is a Python solution for the problem:
class Node:
def __init__(self, data=None):
self.data = data
self.next = None
def is_palindrome(head):
# Initialize a variable to store the combined string
combined_string = ""
# Traverse the linked list
current = head
while current:
# Append the data of each node to the combined string
combined_string += current.data
current = current.next
# Check if the combined string is a palindrome
return combined_string == combined_string[::-1]
This solution works by traversing the linked list and appending the data of each node to a string. It then checks if this string is the same when reversed, which is the definition of a palindrome. The time complexity is O(n) because we have to traverse the entire linked list, and the space complexity is also O(n) because we are storing the combined string.
Similar Questions
You are given a singly linked list, determine if it is a palindrome.A palindrome is a word, phrase, number, or other sequences of characters that reads the same forward and backward (ignoring spaces, punctuation, and capitalization).Write a function that takes the head of a linked list as input and returns True if the linked list is a palindrome, and False otherwise.Sample input:4 //size1 2 2 1 //listOutput:TrueExplanation:The linked list reads the same forward and backward, making it a palindrome.
Given the head of a singly linked list, return true if it is a palindrome or false otherwise. Example 1:Input: head = [1,2,2,1]Output: trueExample 2:Input: head = [1,2]Output: false
Write a python program to check the given string is palindrome or not.
Given a list of words, find all pairs of unique indices such that the concatenation of the two words is a palindrome.For example,given the list ["code", "edoc", "da", "d"], return [(0, 1), (1, 0), (2, 3)].Sample Test CasesTest Case 1:Expected Output:Enter·the·words·of·the·list·separated·by·space:·code edoc da dPairs·of·unique·indices·that·make·palindrome·are:·[(0,·1),·(1,·0),·(2,·3)]
Palindrome CheckerReturn true if the given string is a palindrome. Otherwise, return false.A palindrome is a word or sentence that's spelled the same way both forward and backward, ignoring punctuation, case, and spacing.Note: You'll need to remove all non-alphanumeric characters (punctuation, spaces and symbols) and turn everything into the same case (lower or upper case) in order to check for palindromes.We'll pass strings with varying formats, such as racecar, RaceCar, and race CAR among others.We'll also pass strings with special symbols, such as 2A3*3a2, 2A3 3a2, and 2_A3*3#A2.
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