6 burgers, 2 French fries and 8 ice - creams cost Rs. 240. 4 burgers, 3 French fries and  12 ice - creams cost Rs 240. Find the cost of 2 burgers, 1 French fries and 4 ice creams.

Let's denote the cost of a burger as B, the cost of French fries as F, and the cost of an ice cream as I.

From the first statement, we can form the equation: 6B + 2F + 8I = 240

From the second statement, we can form the equation: 4B + 3F + 12I = 240

We can multiply the first equation by 3 and the second equation by 2 to make the coefficients of F the same in both equations:

18B + 6F + 24I = 720 8B + 6F + 24I = 480

Now, we can subtract the second equation from the first to find the cost of a burger:

10B = 240 B = 24

Substitute B = 24 into the first equation:

6*24 + 2F + 8I = 240 144 + 2F + 8I = 240 2F + 8I = 96 F + 4I = 48

Substitute B = 24 into the second equation:

4*24 + 3F + 12I = 240 96 + 3F + 12I = 240 3F + 12I = 144 F + 4I = 48

From the above, we can see that F + 4I = 48, which is the same as the equation we got from substituting B into the first equation. This means that the cost of French fries (F) is 0.

Substitute F = 0 into the equation F + 4I = 48:

0 + 4I = 48 I = 12

So, the cost of a burger is Rs. 24, the cost of French fries is Rs. 0, and the cost of an ice cream is Rs. 12.

Finally, to find the cost of 2 burgers, 1 French fries, and 4 ice creams, we can substitute the costs into the equation:

2B + F + 4I = 224 + 0 + 412 = 48 + 48 = Rs. 96.