The total impedance (ZT) of a series network consisting of a resistor (R), an inductor (L), and a capacitor (C) can be calculated using the formula:

ZT = sqrt[(R^2) + (XL - XC)^2]

where:
- R is the resistance,
- XL is the reactance of the inductor, and
- XC is the reactance of the capacitor.

Given that R = 5 Ω, XL = 10 Ω, and XC = 15 Ω, we can substitute these values into the formula:

ZT = sqrt[(5^2) + (10 - 15)^2]
= sqrt[(25) + (-5)^2]
= sqrt[(25) + (25)]
= sqrt[50]

Therefore, the total impedance ZT of the series network is sqrt[50] or approximately 7.07 Ω.

Question

The total impedance (ZT) of a series network consisting of a resistor (R), an inductor (L), and a capacitor (C) can be calculated using the formula:

ZT = sqrt[(R^2) + (XL - XC)^2]

where:
- R is the resistance,
- XL is the reactance of the inductor, and
- XC is the reactance of the capacitor.

Given that R = 5 Ω, XL = 10 Ω, and XC = 15 Ω, we can substitute these values into the formula:

ZT = sqrt[(5^2) + (10 - 15)^2]
   = sqrt[(25) + (-5)^2]
   = sqrt[(25) + (25)]
   = sqrt[50]

Therefore, the total impedance ZT of the series network is sqrt[50] or approximately 7.07 Ω.

Knowee AI · Accepted Answer

The total impedance (ZT) of a series network consisting of a resistor (R), an inductor (L), and a capacitor (C) can be calculated using the formula:

ZT = sqrt[(R^2) + (XL - XC)^2]

where:
- R is the resistance,
- XL is the reactance of the inductor, and
- XC is the reactance of the capacitor.

Given that R = 5 Ω, XL = 10 Ω, and XC = 15 Ω, we can substitute these values into the formula:

ZT = sqrt[(5^2) + (10 - 15)^2]
   = sqrt[(25) + (-5)^2]
   = sqrt[(25) + (25)]
   = sqrt[50]

Therefore, the total impedance ZT of the series network is sqrt[50] or approximately 7.07 Ω.

What is the total impedance ZT of a series network consisting of a 5 Ω resistor, an inductor having 10 Ω reactance, and a capacitor with 15 Ω reactance?