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The table gives a set of outcomes and their probabilities. Let A be the event "the outcome is a divisor of 6". Find P(A).Outcome Probability1 0.0292 0.1523 0.194 0.1675 0.2086 0.0067 0.0398 0.209

Question

The table gives a set of outcomes and their probabilities. Let A be the event "the outcome is a divisor of 6". Find P(A).Outcome Probability1 0.0292 0.1523 0.194 0.1675 0.2086 0.0067 0.0398 0.209

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Solution

The divisors of 6 are 1, 2, 3, and 6.

From the table, we can see that:

  • The probability of the outcome being 1 is 0.029.
  • The probability of the outcome being 2 is 0.152.
  • The probability of the outcome being 3 is 0.194.
  • The probability of the outcome being 6 is 0.006.

To find the probability of event A, which is the event that the outcome is a divisor of 6, we add up these probabilities.

So, P(A) = P(1) + P(2) + P(3) + P(6) = 0.029 + 0.152 + 0.194 + 0.006 = 0.381.

Therefore, the probability of the outcome being a divisor of 6 is 0.381.

This problem has been solved

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