What would be the result of the following code snippet?int[] ages = {50, 40, 30, 20, 10};Arrays.sort(ages);int location = Arrays.binarySearch(ages, 20);System.out.println(location);a.)2b.)1c.)3d.)4
Question
What would be the result of the following code snippet?int[] ages = {50, 40, 30, 20, 10};Arrays.sort(ages);int location = Arrays.binarySearch(ages, 20);System.out.println(location);a.)2b.)1c.)3d.)4
Solution
The result of the code snippet would be option c.)3.
Here's the step by step explanation:
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An integer array named 'ages' is declared and initialized with the values {50, 40, 30, 20, 10}.
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The Arrays.sort(ages) method is called. This method sorts the 'ages' array in ascending order. So after this step, the 'ages' array would look like this: {10, 20, 30, 40, 50}.
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The Arrays.binarySearch(ages, 20) method is called. This method performs a binary search on the sorted 'ages' array for the value 20. The binary search algorithm works by repeatedly dividing in half the portion of the array that could contain the item, until you've narrowed down the possible locations to just one. In a zero-based index array like 'ages', the index of 20 is 1.
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The value of 'location' (which is the index of the value 20 in the 'ages' array) is printed. Since arrays in Java are zero-indexed, the index of 20 is 1, not 3.
So, the correct answer should be b.)1, not c.)3.
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