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SSTR = 6,750H0: u1=u2=u3=u4SSE = 8,000Ha: at least one mean is differentnT = 20  The test statistic to test the null hypothesis equalsGroup of answer choices0.840.224.54.22

Question

SSTR = 6,750H0: u1=u2=u3=u4SSE = 8,000Ha: at least one mean is differentnT = 20  The test statistic to test the null hypothesis equalsGroup of answer choices0.840.224.54.22

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Solution

The question seems to be asking for the test statistic in an ANOVA (Analysis of Variance) test.

The formula for the test statistic (F) in an ANOVA test is:

F = (SSTR/(k-1)) / (SSE/(nT-k))

where:

  • SSTR is the sum of squares due to regression,
  • SSE is the sum of squares due to error,
  • k is the number of groups, and
  • nT is the total number of observations.

From the question, we know that:

  • SSTR = 6,750
  • SSE = 8,000
  • nT = 20
  • k is not given, but we can infer from the null hypothesis (H0: u1=u2=u3=u4) that there are 4 groups, so k = 4.

Substituting these values into the formula gives:

F = (6750/(4-1)) / (8000/(20-4)) = 2250 / 500 = 4.5

So, the test statistic to test the null hypothesis is 4.5.

This problem has been solved

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