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Alice opened a savings account and deposited $800.00 as principal. The account earns 10% interest, compounded quarterly. What is the balance after 10 years?Use the formula A=P1+rnnt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years.Round your answer to the nearest cent.

Question

Alice opened a savings account and deposited $800.00 as principal. The account earns 10% interest, compounded quarterly. What is the balance after 10 years?Use the formula A=P1+rnnt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years.Round your answer to the nearest cent.

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Solution

To solve this problem, we need to plug the given values into the formula for compound interest.

Here are the values we know:

  • P (principal) = $800.00
  • r (interest rate) = 10% = 0.10 (as a decimal)
  • n (number of times per year that the interest is compounded) = 4 (quarterly means 4 times a year)
  • t (time in years) = 10 years

Now we can plug these values into the formula:

A = P(1 + r/n)^(nt)

A = 800(1 + 0.10/4)^(4*10)

First, calculate the value inside the parentheses:

1 + 0.10/4 = 1.025

Then raise this value to the power of 4*10:

(1.025)^(4*10) = 2.68564

Finally, multiply this by the principal:

800 * 2.68564 = $2148.51

So, the balance in Alice's savings account after 10 years will be approximately $2148.51, rounded to the nearest cent.

This problem has been solved

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