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Convert one nanometre (1 nm) into metres.106 m10-9 m109 m10-6 m2Convert 4.2 GJ (gigajoules) into joules.4,200,000,000 J4.2 × 10-9 J4,200,000 J4,200,000,000,000 J3Write 590,000 kg in standard form.5.9 × 104 kg5.9 × 105 kg5.9 × 1010 kg5.9 × 106 kg4Write 1.975 A to two significant figures.1.98 A1.9 A1.97 A2.0 A5Calculate the number of seconds in one week.86,400 s604,800 s10,800 s168 s6Convert a temperature of 300 K (kelvin) into degrees Celsius (°C).273 °C27 °C-273 °C-27 °C

Question

Convert one nanometre (1 nm) into metres.106 m10-9 m109 m10-6 m2Convert 4.2 GJ (gigajoules) into joules.4,200,000,000 J4.2 × 10-9 J4,200,000 J4,200,000,000,000 J3Write 590,000 kg in standard form.5.9 × 104 kg5.9 × 105 kg5.9 × 1010 kg5.9 × 106 kg4Write 1.975 A to two significant figures.1.98 A1.9 A1.97 A2.0 A5Calculate the number of seconds in one week.86,400 s604,800 s10,800 s168 s6Convert a temperature of 300 K (kelvin) into degrees Celsius (°C).273 °C27 °C-273 °C-27 °C

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Solution

  1. One nanometre (1 nm) is equal to 10^-9 metres. So, the correct answer is 10^-9 m.

  2. 1 GJ (gigajoule) is equal to 10^9 joules. Therefore, 4.2 GJ is equal to 4.2 x 10^9 joules, which is 4,200,000,000 J.

  3. 590,000 kg in standard form is 5.9 x 10^5 kg.

  4. 1.975 A to two significant figures is 1.98 A.

  5. There are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and 7 days in a week. Therefore, the number of seconds in one week is 60 x 60 x 24 x 7 = 604,800 s.

  6. The Kelvin scale starts at absolute zero, which is -273.15 degrees Celsius. Therefore, a temperature of 300 K is equal to 300 - 273.15 = 26.85 °C, which is approximately 27 °C.

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