A box slides down a rough ramp.The change in the gravitational potential energy of the box is 16 J as it moves between positionsX and Y. The box has 24 J of kinetic energy at X and 35 J of kinetic energy at Y.boxrampXYHow much work is done against the frictional force?A 5 J B 19 J C 27 J D 43 J
Question
A box slides down a rough ramp.The change in the gravitational potential energy of the box is 16 J as it moves between positionsX and Y. The box has 24 J of kinetic energy at X and 35 J of kinetic energy at Y.boxrampXYHow much work is done against the frictional force?A 5 J B 19 J C 27 J D 43 J
Solution
To solve this problem, we need to understand the principle of conservation of energy. The total energy of the box at position X should be equal to the total energy of the box at position Y, assuming no other forces are at work.
At position X, the box has 24 J of kinetic energy and 16 J of potential energy (since it loses this amount moving to Y), giving a total of 40 J.
At position Y, the box has 35 J of kinetic energy. If the total energy is conserved, it should also have 5 J of potential energy remaining, giving a total of 40 J.
However, we know that the box has lost all its potential energy moving from X to Y, so the 5 J must have been used to do work against the frictional force.
Therefore, the work done against the frictional force is 5 J. The answer is A: 5 J.
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