Cayley pushes and object with a force of 40 N right, and her friend pushed in the same direction with an equal force. What is the net force being applied to the object?A40 N rightB0 NC80 N leftD80 N right
Question
Cayley pushes and object with a force of 40 N right, and her friend pushed in the same direction with an equal force. What is the net force being applied to the object?A40 N rightB0 NC80 N leftD80 N right
Solution
The net force applied to an object is the sum of all the forces acting on it. If Cayley pushes the object with a force of 40 N to the right, and her friend also pushes it with a force of 40 N to the right, the two forces add up because they are in the same direction.
So, 40 N (Cayley's force) + 40 N (her friend's force) = 80 N to the right.
Therefore, the correct answer is D80 N right.
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