Radon (Rn) decays in a first-order process with a half-life of 3.823 days. What is thevalue of the rate constant in days -1 ?
Question
Radon (Rn) decays in a first-order process with a half-life of 3.823 days. What is thevalue of the rate constant in days -1 ?
Solution
The rate constant (k) for a first-order reaction can be calculated using the formula:
k = 0.693 / t1/2
where t1/2 is the half-life of the reaction. In this case, the half-life (t1/2) of Radon (Rn) is 3.823 days.
So, substituting the given half-life into the formula, we get:
k = 0.693 / 3.823
After performing the division, we find that the rate constant (k) is approximately 0.181 days^-1.
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