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What is the commutation relationship between the total angular momentum operator L2 and any of its components, e.g., Lx​?OPTIONS [L2,Lx​]= -iℏLx [L2,Lx​]=0 [L2,Lx​]= iℏLx [L2,Lx​]= ℏ

Question

What is the commutation relationship between the total angular momentum operator L2 and any of its components, e.g., Lx​?OPTIONS [L2,Lx​]= -iℏLx [L2,Lx​]=0 [L2,Lx​]= iℏLx [L2,Lx​]= ℏ

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Solution

The commutation relationship between the total angular momentum operator L^2 and any of its components, for example Lx, is [L^2, Lx] = 0. This means that the total angular momentum operator and any of its components commute, i.e., the order in which they are applied does not matter.

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Which of the following commutation relations holds for the angular momentum operators in quantum mechanics?OPTIONS [Lx, Ly] = iħLz [Lx, Ly] = 0 [Lx, Ly] = -iħLz [Lx, Ly] = iħ

Is it possible measure simultaneously square of angular momentum and its x projection ( ^L2 and ^Lx )?Why? Proof.

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