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1/R1=1/(50+688.08j)+1/(-6605.98j) 求R1

Question

1/R1=1/(50+688.08j)+1/(-6605.98j) 求R1

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Solution

To solve for R1, we first need to add the two complex numbers on the right side of the equation.

The complex numbers are 1/(50+688.08j) and 1/(-6605.98j).

Step 1: Find the reciprocal of the complex numbers

Reciprocal of (50+688.08j) = 0.0014 - 0.0192j Reciprocal of (-6605.98j) = 0 - 0.00015j

Step 2: Add the two complex numbers

(0.0014 - 0.0192j) + (0 - 0.00015j) = 0.0014 - 0.01935j

Step 3: The reciprocal of the result is R1

R1 = 1 / (0.0014 - 0.01935j)

To find the reciprocal of a complex number, we multiply the numerator and denominator by the conjugate of the denominator.

R1 = 1 * (0.0014 + 0.01935j) / ((0.0014 - 0.01935j) * (0.0014 + 0.01935j))

Solving the above expression gives:

R1 = (0.0014 + 0.01935j) / (0.0014^2 + 0.01935^2)

R1 = (0.0014 + 0.01935j) / (0.00000196 + 0.000374)

R1 = (0.0014 + 0.01935j) / 0.000376

R1 = 3720.21 + 51439.36j

So, R1 = 3720.21 + 51439.36j.

This problem has been solved

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