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A 50 foot ladder is set against the side of a house so that it reaches up 48 feet. If Mila grabs the ladder at its base and pulls it 6 feet farther from the house, how far up the side of the house will the ladder reach now? (The answer is not 42 ft.) Round to the nearest tenth of a foot.

Question

A 50 foot ladder is set against the side of a house so that it reaches up 48 feet. If Mila grabs the ladder at its base and pulls it 6 feet farther from the house, how far up the side of the house will the ladder reach now? (The answer is not 42 ft.) Round to the nearest tenth of a foot.

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Solution

This problem can be solved using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Step 1: Identify the sides of the right triangle. In this case, the ladder is the hypotenuse, the house is one side, and the ground is the other side.

Step 2: Use the Pythagorean theorem to find the original distance from the base of the ladder to the house. The original height up the house is 48 feet, and the ladder is 50 feet, so we can set up the equation 50^2 = 48^2 + b^2, where b is the base. Solving for b gives us b = sqrt(50^2 - 48^2) = 14 feet.

Step 3: Now, Mila pulls the ladder 6 feet farther from the house, so the new base length is 14 + 6 = 20 feet.

Step 4: Use the Pythagorean theorem again to find the new height up the house. We know the ladder is still 50 feet and the base is now 20 feet, so we can set up the equation 50^2 = h^2 + 20^2, where h is the new height. Solving for h gives us h = sqrt(50^2 - 20^2) = 46.67 feet.

So, after Mila pulls the ladder 6 feet farther from the house, it will reach approximately 46.7 feet up the side of the house.

This problem has been solved

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