A disk rotates at a speed of 6000 rpm(revolutions per minute). It has a seek timeof 10 milliseconds. The disk has 100 trackswith each track having 200 sectors. Findthe average access time of this disk.

To calculate the average access time of the disk, we need to consider both the seek time and the rotational latency.

1. Seek Time: This is given as 10 milliseconds.

2. Rotational Latency: This is the time it takes for the desired sector of a disk to rotate into position under the read/write head. It's typically taken as half the time for a full rotation.

First, we need to convert the speed of the disk from revolutions per minute (rpm) to revolutions per second because our seek time is given in milliseconds (thousandths of a second).

6000 rpm = 6000 revolutions/60 seconds = 100 revolutions per second.

The time for one full revolution (in milliseconds) is therefore 1/100 seconds = 10 milliseconds.

So, the average rotational latency is half of this, which is 5 milliseconds.

3. Average Access Time: This is the sum of the seek time and the average rotational latency.

Average Access Time = Seek Time + Rotational Latency = 10 milliseconds + 5 milliseconds = 15 milliseconds.

So, the average access time of the disk is 15 milliseconds.