If the cost price of an item is $840, the mark up is 15% and the discount is 10%, then find the profit percent. Ops: A. 6.2% B. 7% C. 3.5% D. 4.8% Q 05. The ratio of water and oil in a mixture of 72 litres is 11 : 13 . How many litres of water must be added to the mixture to make the ratio 5 : 4? Ops: A. 22.75 litres B. 19.56 litres C. 15.75 litres D. 14.89 litres
Question
If the cost price of an item is $840, the mark up is 15% and the discount is 10%, then find the profit percent. Ops: A. 6.2% B. 7% C. 3.5% D. 4.8%
Q 05. The ratio of water and oil in a mixture of 72 litres is 11 : 13 . How many litres of water must be added to the mixture to make the ratio 5 : 4? Ops: A. 22.75 litres B. 19.56 litres C. 15.75 litres D. 14.89 litres
Solution
Sure, let's solve these problems one by one.
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First, we need to find the selling price of the item. The markup is 15% of the cost price, so the selling price before discount is 840 = 126 = $966.
Then, the discount is 10% of this selling price, so the final selling price is 966 = 96.6 = $869.4.
The profit is the final selling price minus the cost price, which is 840 = $29.4.
The profit percent is the profit divided by the cost price, times 100%, which is 840 * 100% = 3.5%. So, the answer is C. 3.5%.
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The ratio of water to oil in the mixture is 11 : 13, so there are 11/24 * 72 = 33 litres of water and 13/24 * 72 = 39 litres of oil.
We want to add water to make the ratio 5 : 4. Let's denote the amount of water to be added as x. Then, we have (33 + x) / 39 = 5 / 4.
Solving this equation, we get x = 39 * 5 / 4 - 33 = 48.75 - 33 = 15.75 litres. So, the answer is C. 15.75 litres.
Similar Questions
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f the cost price of an item is $840, the mark up is 15% and the discount is 10%, then find the profit percent. Ops: A. 3.5% B. 4.8% C. 7% D. 6.2%
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