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How many times the  H.C.F of the fractions 6/28,12/70 and 32/42 is their L.C.M?*1) 14402) 1443) 2104) 48

Question

How many times the  H.C.F of the fractions 6/28,12/70 and 32/42 is their L.C.M?*1) 14402) 1443) 2104) 48

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Solution

To solve this problem, we first need to find the H.C.F (Highest Common Factor) and L.C.M (Least Common Multiple) of the given fractions.

Step 1: Simplify the fractions 6/28 simplifies to 3/14 12/70 simplifies to 6/35 32/42 simplifies to 16/21

Step 2: Find the H.C.F of the fractions The H.C.F of fractions is calculated as H.C.F of numerators / L.C.M of denominators. H.C.F of 3, 6, and 16 is 1 L.C.M of 14, 35, and 21 is 210 So, H.C.F of the fractions is 1/210

Step 3: Find the L.C.M of the fractions The L.C.M of fractions is calculated as L.C.M of numerators / H.C.F of denominators. L.C.M of 3, 6, and 16 is 48 H.C.F of 14, 35, and 21 is 1 So, L.C.M of the fractions is 48/1 = 48

Step 4: Find how many times the H.C.F is the L.C.M To do this, divide the L.C.M by the H.C.F. 48 / (1/210) = 48 * 210 = 10080

So, the H.C.F of the fractions is 10080 times their L.C.M. This option is not listed in the given choices. There might be a mistake in the problem or the options provided.

This problem has been solved

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