Which statement is most likely to be true for this distribution?A.The mean is greater than the median.B.The mean is the same as the median.C.The mean is less than the median.
Question
Which statement is most likely to be true for this distribution?A.The mean is greater than the median.B.The mean is the same as the median.C.The mean is less than the median.
Solution
To answer this question, we need to know the shape of the distribution.
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If the distribution is symmetrical (like a normal distribution), then the mean and the median are the same. So, statement B would be true.
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If the distribution is positively skewed (right-skewed), then the mean is greater than the median. So, statement A would be true.
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If the distribution is negatively skewed (left-skewed), then the mean is less than the median. So, statement C would be true.
Without knowing the shape of the distribution, we cannot definitively say which statement is most likely to be true.
Similar Questions
Which of the following statements about the median is not true?Question 13Select one:a.It is equal to the mode in bell-shaped "normal" distributionsb.It is equal to Q2c.It is more affected by extreme values than the meand.It is a measure of central tendency
Are the mean and the median the exact same in this distribution? Why or why not?Yes, they are equal because the distribution is perfectly symmetrical.Yes, they are equal because the distribution is not perfectly symmetrical. No, the mean is less than the median because the distribution is perfectly symmetrical.No, the median is less than the mean because the distribution is not perfectly symmetrical.No, the mean is less than the median because the distribution is not perfectly symmetrical.
In a distribution with a left skew, the mean is most likely ________ the medianQuestion 13Select one:a.approximately the same asb.larger thanc.smaller than
What can we say about the distribution when the mean and median are different?
Which of the following statements is true?Group of answer choicesA. When the distribution is skewed to the left, mean > median > mode.B. When the distribution is skewed to the right, mean < median < mode.C. When the distribution is symmetric and unimodal, mean = median = mode.D. When the distribution is symmetric and bimodal, mean = median = mode.E. None of the above is correct.
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