The number of bromide ions in 3.5 moles of MgBr2 is

Sure, here's how you can calculate the number of bromide ions in 3.5 moles of MgBr2:

1. First, you need to understand the formula MgBr2. This tells you that there are two bromide ions (Br-) for every one magnesium ion (Mg2+).

2. Therefore, in one mole of MgBr2, there are two moles of bromide ions.

3. To find the number of bromide ions in 3.5 moles of MgBr2, you simply multiply the number of moles of MgBr2 by the number of bromide ions per mole of MgBr2.

   So, 3.5 moles of MgBr2 * 2 moles of Br- per mole of MgBr2 = 7 moles of Br-.

4. Finally, to convert moles to ions, you use Avogadro's number, which is 6.022 x 10^23. This is the number of particles in one mole.

   So, 7 moles of Br- * 6.022 x 10^23 ions per mole = 4.2154 x 10^24 bromide ions.

So, there are 4.2154 x 10^24 bromide ions in 3.5 moles of MgBr2.