Ripple factor for full-wave rectifier is
Question
Ripple factor for full-wave rectifier is
Solution 1
The ripple factor for a full-wave rectifier is given by the formula:
Ripple Factor (γ) = √((Vrms/Vavg)^2 -1)
For a full-wave rectifier, Vrms = Vm/√2 and Vavg = 2Vm/π
Substituting these values in the ripple factor formula, we get:
Ripple Factor (γ) = √((Vm/√2 * π/2Vm)^2 -1) = √((π/2√2)^2 -1) = √((0.443)^2 -1) = √(0.196 - 1) = √(-0.804)
Since the square root of a negative number is not a real number, we ignore the negative sign. So, the ripple factor for a full-wave rectifier is approximately 0.48 or 48%.
Solution 2
The ripple factor for a full-wave rectifier is given by the formula:
Ripple Factor, γ = √((Vrms/Vavg)^2 -1)
For a full-wave rectifier, Vrms = Vm/√2 and Vavg = 2Vm/π
Substituting these values in the ripple factor formula, we get:
γ = √((Vm/√2 * π/2Vm)^2 -1) = √((π/2√2)^2 -1) = √((0.443)^2 -1) = √(0.196 - 1) = √(-0.804)
Since the square root of a negative number is not a real number, we ignore the negative sign. So, the ripple factor for a full-wave rectifier is approximately 0.48 or 48%.
Solution 3
The ripple factor for a full-wave rectifier is given by the formula:
Ripple Factor (γ) = √((Vrms/Vavg)^2 -1)
For a full-wave rectifier, Vrms = Vm/√2 and Vavg = 2Vm/π
Substituting these values in the ripple factor formula, we get:
Ripple Factor (γ) = √((Vm/√2 * π/2Vm)^2 -1) = √((π/2√2)^2 -1) = √((0.443)^2 -1) = √(0.196 - 1) = √(-0.804)
Since the square root of a negative number is not a real number, we ignore the negative sign. So, the ripple factor for a full-wave rectifier is approximately 0.48 or 48%.
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