Let f, g : R → R be continuous functions such that f (a)̸ = g(a) for somea ∈ R. Show that ∃ a δ > 0 such that f (x)̸ = g(x), ∀x such that |x − a| < δ
Question
Let f, g : R → R be continuous functions such that f (a)̸ = g(a) for somea ∈ R. Show that ∃ a δ > 0 such that f (x)̸ = g(x), ∀x such that |x − a| < δ
Solution
Since f and g are continuous functions, we can use the property of continuity to prove the statement.
Step 1: Define the function h(x) = f(x) - g(x). Since f and g are continuous, h is also continuous.
Step 2: We know that h(a) = f(a) - g(a) ≠ 0.
Step 3: Because h is continuous and h(a) ≠ 0, we can apply the property of continuity which states that for any ε > 0, there exists a δ > 0 such that if |x - a| < δ, then |h(x) - h(a)| < ε.
Step 4: Choose ε = |h(a)|. Then there exists a δ > 0 such that if |x - a| < δ, then |h(x) - h(a)| < |h(a)|.
Step 5: This implies that h(x) ≠ 0 for all x such that |x - a| < δ. In other words, f(x) ≠ g(x) for all x such that |x - a| < δ.
Therefore, we have shown that there exists a δ > 0 such that f(x) ≠ g(x) for all x such that |x - a| < δ.
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