Consider the situation in the diagram. Block 1 has mass m1and is on a slope at an angle θ from horizontal. Block 2 hasmass m2 .Find an expression for the acceleration of the blocks, ignor-ing friction.You will be marked on the following:1) Free body diagram for block 1.2) Free-body diagram for block 2.3) Relevant equations for block 1.4) Relevant equations for block 2.5) Solving the equations for acceleration.

A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and θ for the block to remain stationary on the wedge is :-    [2018]A: B: C: a = g cos θD: a = g tan θ

A block of mass 2.30 kg slides down a slope at an angle of 33° to the horizontal, with a constant velocity of 1.0 m s–1. Calculate the coefficient of dynamic friction between the slope and the block and express your answer to two significant figures.

Block 1 and Block 2 have the same mass, m, and are released from the top of two inclined planes of the same height making 30o and 60o angles with the horizontal directoin, respectively. If the coefficient of friction is the same in both cases, which of the blocks is going faster when it reaches the bottom of its respective incline? Block 1 is faster Block 2 is faster. More information is needed to know which block is faster. Both blocks have the same speed at the bottom.

Two blocks are arranged as below, connected together by rope and pulley with m1 = 3.50 kg and m2 = 7.00 kg. The coefficient of kinetic friction between all surfaces is 0.250. The top block is pulled to the right with a force F = 69.2 N. What is the acceleration of the top block?

The diagram below shows a block of mass m=2.00kg𝑚=2.00kg on a frictionless horizontal surface, as seen from above. Three forces of magnitudes F1=4.00N𝐹1=4.00N, F2=6.00N𝐹2=6.00N, and F3=8.00N𝐹3=8.00N are applied to the block, initially at rest on the surface, at angles shown on the diagram. (Figure 1) In this problem, you will determine the resultant (total) force vector from the combination of the three individual force vectors. All angles should be measured counterclockwise from the positive x axis (i.e., all angles are positive).Figure1 of 1Part APart completeCalculate the magnitude of the total resultant force F⃗ r=F⃗ 1+F⃗ 2+F⃗ 3𝐹→r=𝐹→1+𝐹→2+𝐹→3 acting on the mass.Express your answer in Newtons to three significant figures.View Available Hint(s)for Part A|F⃗ r||𝐹→r| =1.83NNSubmitPrevious AnswersAnswer RequestedPart BPart completeWhat angle does F⃗ r𝐹→r make with the positive x axis?Express your answer in degrees to two significant figures.View Available Hint(s)for Part B-73degreesSubmitPrevious AnswersAll attempts used; correct answer displayedPart CPart completeWhat is the magnitude of the mass's acceleration vector, a⃗ 𝑎→?Express your answer to two significant figures.View Available Hint(s)for Part C|a⃗ ||𝑎→| =0.92m/s2m/s2SubmitPrevious AnswersAll attempts used; correct answer displayedPart DPart completeWhat is the direction of a⃗ 𝑎→? In other words, what angle does this vector make with respect to the positive x axis?Express your answer in degrees to two significant figures.View Available Hint(s)for Part D-73degreesSubmitPrevious AnswersAll attempts used; correct answer displayedPart EHow far (in meters) will the mass move in 5.0 s?Express the distance d𝑑 in meters to two significant figures.View Available Hint(s)for Part EActivate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typed𝑑 =mmSubmitPrevious Answers Incorrect; Try Again; 9 attempts remainingPart FWhat is the magnitude of the velocity vector of the block at t=5.0s𝑡=5.0s?Express your answer in meters per second to two significant figures.View Available Hint(s)for Part FActivate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value type|v⃗ (5)||𝑣→(5)| =m/sm/sSubmitPrevious Answers Incorrect; Try Again; 9 attempts remainingPart GIn what direction is the mass moving at time t=5.0s𝑡=5.0s? That is, what angle does the velocity vector make with respect to the positive x axis?Express your answer in degrees to two significant figures.View Available Hint(s)