Calcium oxide is reacted with water to produced calcium hydroxide, a widely used base:CaO(s) + H2O(l) → Ca(OH)2(s)a. How much calcium hydroxide is produced by the complete reaction of 150.0 g CaO with excess of water?
Question
Calcium oxide is reacted with water to produced calcium hydroxide, a widely used base:CaO(s) + H2O(l) → Ca(OH)2(s)a. How much calcium hydroxide is produced by the complete reaction of 150.0 g CaO with excess of water?
Solution
To solve this problem, we need to use stoichiometry, which is a method in chemistry that uses balanced chemical equations to calculate quantities of reactants or products.
Step 1: Write the balanced chemical equation CaO(s) + H2O(l) → Ca(OH)2(s)
Step 2: Calculate the molar mass of CaO The molar mass of CaO = 40.08 g/mol (for Ca) + 16.00 g/mol (for O) = 56.08 g/mol
Step 3: Convert the mass of CaO to moles 150.0 g CaO * (1 mol CaO / 56.08 g CaO) = 2.67 mol CaO
Step 4: Use the stoichiometry of the reaction to find moles of Ca(OH)2 From the balanced chemical equation, we can see that 1 mol of CaO produces 1 mol of Ca(OH)2. So, 2.67 mol CaO will produce 2.67 mol Ca(OH)2.
Step 5: Convert moles of Ca(OH)2 to grams The molar mass of Ca(OH)2 = 40.08 g/mol (for Ca) + 216.00 g/mol (for O) + 21.01 g/mol (for H) = 74.10 g/mol So, 2.67 mol Ca(OH)2 * 74.10 g/mol = 198 g Ca(OH)2
Therefore, 198 g of calcium hydroxide is produced by the complete reaction of 150.0 g CaO with excess of water.
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