To calculate the hardness in ppm (parts per million) for both samples, we need to convert the mg/L to ppm.

1. For Sample A:
The given concentration is 168 mg of MgCO3 in 500 mL. We need to convert this to mg/L (since 1 ppm = 1 mg/L).
So, 168 mg in 500 mL is equivalent to (168 mg / 0.5 L) = 336 mg/L.
Therefore, the hardness of Sample A is 336 ppm.

2. For Sample B:
The given concentration is 820 mg of Ca(NO3)2 in 250 mL. We need to convert this to mg/L.
So, 820 mg in 250 mL is equivalent to (820 mg / 0.25 L) = 3280 mg/L.
Therefore, the hardness of Sample B is 3280 ppm.

Question

To calculate the hardness in ppm (parts per million) for both samples, we need to convert the mg/L to ppm.

1. For Sample A:
   The given concentration is 168 mg of MgCO3 in 500 mL. We need to convert this to mg/L (since 1 ppm = 1 mg/L). 
   So, 168 mg in 500 mL is equivalent to (168 mg / 0.5 L) = 336 mg/L. 
   Therefore, the hardness of Sample A is 336 ppm.

2. For Sample B:
   The given concentration is 820 mg of Ca(NO3)2 in 250 mL. We need to convert this to mg/L. 
   So, 820 mg in 250 mL is equivalent to (820 mg / 0.25 L) = 3280 mg/L. 
   Therefore, the hardness of Sample B is 3280 ppm.

Knowee AI · Accepted Answer

To calculate the hardness in ppm (parts per million) for both samples, we need to convert the mg/L to ppm.

1. For Sample A:
   The given concentration is 168 mg of MgCO3 in 500 mL. We need to convert this to mg/L (since 1 ppm = 1 mg/L). 
   So, 168 mg in 500 mL is equivalent to (168 mg / 0.5 L) = 336 mg/L. 
   Therefore, the hardness of Sample A is 336 ppm.

2. For Sample B:
   The given concentration is 820 mg of Ca(NO3)2 in 250 mL. We need to convert this to mg/L. 
   So, 820 mg in 250 mL is equivalent to (820 mg / 0.25 L) = 3280 mg/L. 
   Therefore, the hardness of Sample B is 3280 ppm.

The samples A and B were analyzed for their salts contents:Sample A was found to contain 168 mg of magnesium carbonate per 500 mL. Sample B was found tocontain 820 mg of calcium nitrate per 250 mLDetermine the hardness in all above two samples in ppm.Molecular weights: MgCO3=84; Ca(NO3)2=164

Question

Solution

Similar Questions

Upgrade your grade with Knowee