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3.42 g of sucrose are dissolved in 18 g of water in a beaker. The number of oxygen atoms in the solution are :(a) 6.68 × 1023(b) 6.09 × 1022(c) 6.022 × 1023(d) 6.022 × 1021

Question

3.42 g of sucrose are dissolved in 18 g of water in a beaker. The number of oxygen atoms in the solution are :(a) 6.68 × 1023(b) 6.09 × 1022(c) 6.022 × 1023(d) 6.022 × 1021

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Solution

To determine the number of oxygen atoms in the solution, we need to calculate the number of moles of sucrose and water separately.

Step 1: Calculate the number of moles of sucrose. To do this, we need to use the molar mass of sucrose, which is 342.3 g/mol.

Number of moles of sucrose = mass of sucrose / molar mass of sucrose Number of moles of sucrose = 3.42 g / 342.3 g/mol Number of moles of sucrose = 0.01 mol

Step 2: Calculate the number of moles of water. To do this, we need to use the molar mass of water, which is 18.0 g/mol.

Number of moles of water = mass of water / molar mass of water Number of moles of water = 18 g / 18.0 g/mol Number of moles of water = 1 mol

Step 3: Calculate the total number of oxygen atoms. Since each molecule of sucrose (C12H22O11) contains 11 oxygen atoms and each molecule of water (H2O) contains 1 oxygen atom, we can calculate the total number of oxygen atoms in the solution.

Total number of oxygen atoms = (number of moles of sucrose * 11) + (number of moles of water * 1) Total number of oxygen atoms = (0.01 mol * 11) + (1 mol * 1) Total number of oxygen atoms = 0.11 mol + 1 mol Total number of oxygen atoms = 1.11 mol

Step 4: Convert the number of oxygen atoms to scientific notation. The Avogadro's number, which represents the number of particles in one mole of a substance, is 6.022 × 10^23.

Number of oxygen atoms = Total number of oxygen atoms * Avogadro's number Number of oxygen atoms = 1.11 mol * 6.022 × 10^23 Number of oxygen atoms = 6.68 × 10^23

Therefore, the correct answer is (a) 6.68 × 10^23.

This problem has been solved

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