main points and formulae for electric charges and feilds chapter

In nature, the electric charge of any system is always equal to:half integral multiple of the least amount of chargezerosquare of the least amount of chargeintegral multiple of the least amount of charge

Electric field lines from positive charges point radially , and point radially for negative charges.

What are the units for charge? Group of answer choicesOhmCoulombVoltAmpere

When working with electric charges, what symbol is used in equations to represent the charge of an object?A.rB.FeC.ED.q

BackgroundThe electric field 𝐸→ of a particle with charge 𝑞 can be derived from its electric potential 𝑉:𝐸→=−∇𝑉where ∇ is the derivative operator and 𝑉 at every point in space is 𝑉=14𝜋𝜀0𝑞||𝑟→||where 𝑟→ is the distance from the particle at that point, 14𝜋𝜀0 is some constant, and ||𝑟→||=𝑟𝑥2+𝑟𝑦2 (in a two-dimensional plane). The net electric potential at any point is the sum of all of the electric potentials from all the particles.The force from particle 𝐵 on particle 𝐴 is the charge of 𝐴 (𝑞𝐴) multiplied by the electric field from 𝐵: 𝐹→𝐵→𝐴=𝑞𝐴𝐸→𝐵=14𝜋𝜀0𝑞𝐴⋅𝑞𝐵||𝑟→||2𝑟^For this problem, however, you will only visualize the electric potential 𝑉.ProblemGiven two kinds of particles, those with a positive charge +𝑒, and those with negative charges −𝑒, display the electric potential at every point in space. The electric potential should be normalized relative to |𝑒|4𝜋𝜀0 (i.e., treat |𝑒|4𝜋𝜀0 as 1).InputInput starts with 3 integers 𝑛,𝑚,𝑞 where 0<𝑛,𝑚≤50 and 0<𝑞≤10. Then follows 𝑞 lines: each line contains three values 𝑥,𝑦,𝑠, where 1≤𝑥≤𝑚 and 1≤𝑦≤𝑛 correspond to the integer coordinates of the charged particle and 𝑠 is the sign of the particle’s charge being either a + or a -. No two particles will have the same coordinates.OutputYour output should be an 𝑛×𝑚 grid of ASCII characters oriented with the positive 𝑦-axis pointing down and the positive 𝑥-axis pointing to the right, with coordinates starting from 1. Every character in the grid corresponds to the total potential at that point.If the field contains a particle, print either a + or - corresponding to its charge. Otherwise, the character you place will be related to the sign of the potential. If the potential is negative then use the characters {%,X,x}. If it is positive, however, use the character set {0,O,o} (the first element is a zero).There are 3 tiers to the field’s magnitude:1/𝜋1/𝜋21/𝜋3If the field is below the third tier print a “.”.If the magnitude is above the first tier then you would use % or 0 (zero) depending on the sign, if it is below the first tier then you would use X or O, and so on and so forth.Sample Input 1 Sample Output 120 20 25 5 +15 15 -OOOOOOOOOoooo.......OOOOOOOOOoooo.......OOO000OOOOooo.......OO00000OOOooo.......OO00+00OOOoo........OO00000OOooo........OOO000OOOoo....xxxxxOOOOOOOOoo...xxxxxxxOOOOOOOoo...xxxxxxxxooOOOooo...xxxXXXxxxooooooo...xxXXXXXXXxoooooo...xxXXXXXXXXXoooo....xxXXX%%%XXXX.......xxxXX%%%%%XXX.......xxXXX%%-%%XXX......xxxXXX%%%%%XXX......xxxXXXX%%%XXXX......xxxxXXXXXXXXXX......xxxxXXXXXXXXXX......xxxxxXXXXXXXXxSample Input 2 Sample Output 220 20 315 15 -10 10 +5 5 -XXXXXXXXXXxxxxxxxxxxXXXXXXXXXXxxxxxxxxxxXXX%%%XXXXxxxxxxxxxxXX%%%%%XXXxxxxxxxxxxXX%%-%%XXxxxxxxxxxxxXX%%%%%Xxx..xxxxxxxxXXX%%%Xx.oo..xxxxxxxXXXXXXx.OOOo..xxxxxxXXXXXx.O000Oo.xxxxxxXXXXxxoO0+0OoxxXXXXXxxxxx.oO000O.xXXXXXXxxxxx..oOOO.xXXXXXXXxxxxxx..oo.xX%%%XXXXxxxxxxx..xxX%%%%%XXXxxxxxxxxxxXX%%-%%XXXxxxxxxxxxXXX%%%%%XXXxxxxxxxxxXXXX%%%XXXXxxxxxxxxxXXXXXXXXXXXxxxxxxxxxXXXXXXXXXXXxxxxxxxxxXXXXXXXXXXXSample Input 3 Sample Output 320 20 210 2 +10 18 -oooOOOO00000OOOOoooooooOOOO00+00OOOOoooooooOOOO00000OOOOooooooooOOOO000OOOOooooooooooOOOOOOOOOooooooooooooOOOOOOOoooooo..oooooooOOOooooooo......ooooooooooo.....................................................................xxxxxxxxxxx......xxxxxxxXXXxxxxxxx..xxxxxxXXXXXXXxxxxxx.xxxxxXXXXXXXXXxxxxxxxxxxXXXX%%%XXXXxxxxxxxxXXXX%%%%%XXXXxxxxxxxXXXX%%-%%XXXXxxxxxxxXXXX%%%%%XXXXxxxxxxxXXXXX%%%XXXXXxxxx