A 24-g bullet moving at 1,200 m/s is fired through a one-kg block of wood emerging at a speed of 100 m/s. What is the kinetic energy of the block that results from the collision if the block had not been moving prior to the collision and was free to move?Select one:a.​0.01 kJb.0.35 kJc.0.49 kJd.1.05 kJe.0.41 kJ

A 14.0-g bullet is fired into a 1,100-g block of wood which is suspended as a ballistic pendulum. The combined mass swings up to a height of 8.50 cm. What was the kinetic energy of the combined mass immediately after the collision?Select one:a.0.928 Jb.​0.095 Jc.0.012 Jd.0.928 × 103 Je.0.916 J

A bullet of mass 0.020 kg is fired; it strikes the wooden block of 0.50kg and sticksin it. The bullet and wooden block move off together with a velocity of 100 m/ s.What is the momentum of the bullet with wooden block?(A) 2 kg m/ s (B) 50 kg m/ s (C) 52 kg m/ s (D) 70 kg m/ s

A block of mass m = 25 kg has a speed V and is behind a block of mass M = 64 kg that has a speed of 0.50 m/s. The surface is frictionless. The blocks collide and couple.After the collision, the blocks have a common speed of 0.90 m/s. How much kinetic energy is lost in the collision?Express your answer in Joules.

A 10.00-g bullet traveling horizontally at 533 m/s hits a1.00-kg wooden block, which is initially at rest on a rough horizontal surface. The coefficient of kinetic friction between the block and the surface is 0.4. The bullet buries itself in the block without passing through. The distance the block moved on the surface before stopping is:Question 12Select one:a.4.48 mb.6.89 mc.5.86 md.3.45 me.2.41 m

A 1.1 object traveling east at 21 m/s collides with a 4.5 kg object traveling west at 10 m/s. After the collision, the 1.1 kg object has a velocity 3 m/s to the west. How much kinetic energy was lost during the collision?