2a2(b2 – c2) + b2(2c2 – 2a2) + 2c2(a2 – b2)
Question
2a2(b2 – c2) + b2(2c2 – 2a2) + 2c2(a2 – b2)
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Solution
Sure, let's simplify the given expression step by step:
Given expression: 2a²(b² - c²) + b²(2c² - 2a²) + 2c²(a² - b²)
Step 1: Distribute the terms:
= 2a²b² - 2a²c² + 2b²c² - 2a²b² + 2a²c² - 2b²c²
Step 2: Combine like terms:
= 2a²b² - 2a²b² + 2b²c² - 2b²c²
Step 3: Simplify:
= 0
So, the simplified form of the given expression is 0.
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