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2a2(b2 – c2) + b2(2c2 – 2a2) + 2c2(a2 – b2)

Question

2a2(b2 – c2) + b2(2c2 – 2a2) + 2c2(a2 – b2)

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Solution

Sure, let's simplify the given expression step by step:

Given expression: 2a²(b² - c²) + b²(2c² - 2a²) + 2c²(a² - b²)

Step 1: Distribute the terms:

= 2a²b² - 2a²c² + 2b²c² - 2a²b² + 2a²c² - 2b²c²

Step 2: Combine like terms:

= 2a²b² - 2a²b² + 2b²c² - 2b²c²

Step 3: Simplify:

= 0

So, the simplified form of the given expression is 0.

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