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Write the equation of a circle with its center at (-7, 10) and circumference 12π.

Question

Write the equation of a circle with its center at (-7, 10) and circumference 12π.

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Solution

The equation of a circle is given by the formula (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is (-7, 10), we have h = -7 and k = 10.

The circumference of a circle is given by the formula 2πr. Given that the circumference is 12π, we can solve for r:

2πr = 12π r = 12π / 2π r = 6

Substituting h = -7, k = 10, and r = 6 into the equation of a circle, we get:

(x - (-7))² + (y - 10)² = 6² (x + 7)² + (y - 10)² = 36

So, the equation of the circle is (x + 7)² + (y - 10)² = 36.

This problem has been solved

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