The magnitude of a vector in the form v = r(cos θ i + sin θ j) is given by the value of r. In this case, the magnitude of the vector is 7.

The direction angle of the vector is given by the value of θ. In this case, the direction angle of the vector is 82°.

So, the magnitude of the vector is 7 and the direction angle is 82°.

Question

The magnitude of a vector in the form v = r(cos θ i + sin θ j) is given by the value of r. In this case, the magnitude of the vector is 7.

The direction angle of the vector is given by the value of θ. In this case, the direction angle of the vector is 82°.

So, the magnitude of the vector is 7 and the direction angle is 82°.

Knowee AI · Accepted Answer

The magnitude of a vector in the form v = r(cos θ i + sin θ j) is given by the value of r. In this case, the magnitude of the vector is 7.

The direction angle of the vector is given by the value of θ. In this case, the direction angle of the vector is 82°.

So, the magnitude of the vector is 7 and the direction angle is 82°.

Find the magnitude and direction angle (in degrees) of the following vector.v=7(cos(82°)i+sin(82°)j)