Knowee
Questions
Features
Study Tools

Which activation function is most likely to be used in the output layer for a multi-class classification problem?Group of answer choicesSigmoidReLUSoftmaxTanh

Question

Which activation function is most likely to be used in the output layer for a multi-class classification problem?Group of answer choicesSigmoidReLUSoftmaxTanh

🧐 Not the exact question you are looking for?Go ask a question

Solution

The activation function most likely to be used in the output layer for a multi-class classification problem is Softmax. This is because the Softmax function is able to handle multiple classes and provides a set of outputs between 0 and 1 that sum up to 1. This makes it suitable for multi-class classification problems where the output can be one of several discrete classes.

Similar Questions

Which activation function is most likely to be used in the output layer for a multi-class classification problem?

Which activation function is often used in the output layer for multi-class classification problems?Review LaterSigmoidReLUSoftmaxTanh

The ______________ function is often used as an activation function in the output layer of a binary classification problem.

Suppose we use a neural network to classify images of handwritten digits (0-9). Which of the following activation functions is most suitable at the output layer? Softmax ReLU Tanh Sigmoid

8.  A machine learning specialist is training a deep neural network to classify an image into one of the 4 categories available. Which of the following is the best activation functions the specialist can use in the output neuron?softmaxrelusigmoidlinear9. import pandas as pddf =pd.DataFrame( { 'Name': ['Alice', 'Bob', 'Charlie', 'Alice', 'Bob', 'Charlie'], 'Age': [25, 30, 35, 25, 30, 35], 'City': ['New York', 'Los Angeles', 'Chicago', 'New York', 'Los Angeles', 'Chicago'], 'Salary': [70000, 80000, 90000, 75000, 85000, 95000]})Which of the following code snippets correctly calculates the average salary for each city?df.groupby('City').Salary.mean()All of the aboveNone of the abovedf.groupby('City', as_index=False)['Salary'].mean()df.groupby('City').agg({'Salary': 'mean'})df.groupby('City')['Salary'].mean()

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.