What is the perimeter of a triangle with vertices located at (-1, 4), (2, 7), and (1, 5), rounded to the nearest hundredth?A.9.24 unitsB.7.89 unitsC.7.63 unitsD.8.71 unitsSUBMITarrow_backPREVIOUS

To find the perimeter of a triangle with given vertices, we first need to find the distance between each pair of points. The distance between two points (x1, y1) and (x2, y2) can be found using the distance formula: √[(x2-x1)² + (y2-y1)²].

1. Find the distance between (-1, 4) and (2, 7): Distance = √[(2 - (-1))² + (7 - 4)²] = √[9 + 9] = √18 = 4.24 (rounded to the nearest hundredth)

2. Find the distance between (2, 7) and (1, 5): Distance = √[(1 - 2)² + (5 - 7)²] = √[1 + 4] = √5 = 2.24 (rounded to the nearest hundredth)

3. Find the distance between (1, 5) and (-1, 4): Distance = √[(-1 - 1)² + (4 - 5)²] = √[4 + 1] = √5 = 2.24 (rounded to the nearest hundredth)

Finally, add up these distances to find the perimeter of the triangle: Perimeter = 4.24 + 2.24 + 2.24 = 8.72 units

So, the answer is D. 8.71 units (rounded to the nearest hundredth).