The atomic number of Vanadium (V) is 23, which means it has 23 protons.

The superscript 51 in ⁵¹V²⁺ is the atomic mass number, which is the sum of protons and neutrons. So, to find the number of neutrons, subtract the number of protons from the atomic mass number: 51 - 23 = 28 neutrons.

The ²⁺ indicates that the atom has lost 2 electrons, so instead of having 23 electrons (which it would have if it were neutral), it now has 23 - 2 = 21 electrons.

So, ⁵¹V²⁺ has 23 protons, 21 electrons, and 28 neutrons.

Question

The atomic number of Vanadium (V) is 23, which means it has 23 protons.

The superscript 51 in ⁵¹V²⁺ is the atomic mass number, which is the sum of protons and neutrons. So, to find the number of neutrons, subtract the number of protons from the atomic mass number: 51 - 23 = 28 neutrons.

The ²⁺ indicates that the atom has lost 2 electrons, so instead of having 23 electrons (which it would have if it were neutral), it now has 23 - 2 = 21 electrons.

So, ⁵¹V²⁺ has 23 protons, 21 electrons, and 28 neutrons.

Knowee AI · Accepted Answer

The atomic number of Vanadium (V) is 23, which means it has 23 protons.

The superscript 51 in ⁵¹V²⁺ is the atomic mass number, which is the sum of protons and neutrons. So, to find the number of neutrons, subtract the number of protons from the atomic mass number: 51 - 23 = 28 neutrons.

The ²⁺ indicates that the atom has lost 2 electrons, so instead of having 23 electrons (which it would have if it were neutral), it now has 23 - 2 = 21 electrons.

So, ⁵¹V²⁺ has 23 protons, 21 electrons, and 28 neutrons.

What is the number of protons, electrons, and neutrons in ⁵¹V²⁺?

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