Give the exact value of 𝜃=sin−1(−12), assuming that −𝜋2≤𝜃≤𝜋2.𝜃=
Question
Give the exact value of 𝜃=sin−1(−12), assuming that −𝜋2≤𝜃≤𝜋2.𝜃=
Solution
The value of θ = sin^(-1)(-1/2) is -π/6 or -30°. This is because sin(-π/6) = -1/2. The range -π/2 ≤ θ ≤ π/2 is the range of the inverse sine function, which ensures that the value of θ is in the correct range.
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