If a number is selected at random from the first 50 natural numbers, what will be the probability that the selected number is a multiple of 3 and 4?

To solve this problem, we first need to find the numbers that are multiples of both 3 and 4 within the first 50 natural numbers.

The multiples of both 3 and 4 are actually the multiples of 12 (since 12 is the least common multiple of 3 and 4).

So, let's find out how many multiples of 12 are there within 50.

They are: 12, 24, 36, and 48. So, there are 4 such numbers.

The probability of an event is given by the formula:

P(E) = Number of favorable outcomes / Total number of outcomes

Here, the total number of outcomes is 50 (since a number is selected from the first 50 natural numbers), and the number of favorable outcomes is 4 (the multiples of 12 we found).

So, the probability P(E) = 4 / 50 = 0.08

So, the probability that the selected number is a multiple of 3 and 4 is 0.08.