On the top of the tower 100 meters high, Brianne saw and fell in love with Jo who is sitting under the tree. How far is Jo from the tower if the angle of depression formed by Brianne’s line of sight with the horizontal is 30°?
Question
On the top of the tower 100 meters high, Brianne saw and fell in love with Jo who is sitting under the tree. How far is Jo from the tower if the angle of depression formed by Brianne’s line of sight with the horizontal is 30°?
Solution
To solve this problem, we can use the properties of a 30-60-90 triangle. In a 30-60-90 triangle, the ratio of the sides opposite the 30°, 60°, and 90° angles is 1:√3:2.
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First, we know that the height of the tower is 100 meters, which corresponds to the side opposite the 60° angle (since the angle of depression and the angle of elevation are complementary).
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We want to find the distance from the tower to Jo, which corresponds to the side adjacent to the 60° angle (or opposite the 30° angle).
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Using the ratio of the sides in a 30-60-90 triangle, we know that the side opposite the 30° angle is half the length of the side opposite the 90° angle.
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Therefore, the distance from the tower to Jo is half the height of the tower, or 100 meters / 2 = 50 meters.
So, Jo is 50 meters away from the tower.
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