To solve this problem, we can set up a system of linear equations based on the information given.

Let's denote the price of a child's ticket as C and the price of an adult's ticket as A.

From the information given for Monday, we can write the first equation as:
39C + 25A = 89

From the information given for Tuesday, we can write the second equation as:
32C + 25A = 82

Now we have a system of two equations, and we can solve it step by step.

First, let's subtract the second equation from the first one:
(39C + 25A) - (32C + 25A) = 89 - 82
This simplifies to:
7C = 7
So, C = 1

Now that we know C = 1, we can substitute it into the first equation:
39*1 + 25A = 89
This simplifies to:
25A = 89 - 39
25A = 50
So, A = 50 / 25 = 2

Therefore, the admission price for children is $1 and for adults is $2.

Question

To solve this problem, we can set up a system of linear equations based on the information given.

Let's denote the price of a child's ticket as C and the price of an adult's ticket as A.

From the information given for Monday, we can write the first equation as:
39C + 25A = 89

From the information given for Tuesday, we can write the second equation as:
32C + 25A = 82

Now we have a system of two equations, and we can solve it step by step.

First, let's subtract the second equation from the first one:
(39C + 25A) - (32C + 25A) = 89 - 82
This simplifies to:
7C = 7
So, C = 1

Now that we know C = 1, we can substitute it into the first equation:
39*1 + 25A = 89
This simplifies to:
25A = 89 - 39
25A = 50
So, A = 50 / 25 = 2

Therefore, the admission price for children is $1 and for adults is $2.

Knowee AI · Accepted Answer