The reaction of XeF4 and O2F2 at 143 K give a xenon compound (P). The number of mole of HF produced by the complete hydrolysis of 1 mol of P is___
Question
The reaction of XeF4 and O2F2 at 143 K give a xenon compound (P). The number of mole of HF produced by the complete hydrolysis of 1 mol of P is___
Solution
To determine the number of moles of HF produced by the complete hydrolysis of 1 mole of compound P, we need to first understand the reaction between XeF4 and O2F2.
The reaction can be represented as follows: XeF4 + O2F2 → P
From the given information, we know that the reaction occurs at a temperature of 143 K.
Next, we need to consider the hydrolysis of compound P. Hydrolysis is a chemical reaction in which a compound reacts with water to produce other compounds. In this case, we are interested in the production of HF.
The hydrolysis reaction of compound P can be represented as follows: P + H2O → HF + other products
Since we are interested in the number of moles of HF produced, we can assume that the reaction goes to completion and that 1 mole of compound P will produce 1 mole of HF.
Therefore, the number of moles of HF produced by the complete hydrolysis of 1 mole of compound P is 1 mole.
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