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Algebraic expressions (Part 2): ExponentsDIVIDING POWERSSimplify the following expression:16g5(8g3)216๐‘”5(8๐‘”3)2INSTRUCTIONS: If necessary:Use the ^ symbol to type an exponent. For example for g2๐‘”2 type g^2.Use brackets to put multiple factors in the denominator. For example, to get 12g12๐‘” type 1/(2 g).Answer: 2 attempts remaining

Question

Algebraic expressions (Part 2): ExponentsDIVIDING POWERSSimplify the following expression:16g5(8g3)216๐‘”5(8๐‘”3)2INSTRUCTIONS: If necessary:Use the ^ symbol to type an exponent. For example for g2๐‘”2 type g^2.Use brackets to put multiple factors in the denominator. For example, to get 12g12๐‘” type 1/(2 g).Answer: 2 attempts remaining

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Solution

The given expression is 16g^5(8g^3)^2.

First, simplify the expression inside the parentheses.

(8g^3)^2 = 64g^6 (because (a^m)^n = a^(mn) and (8^2)(g^(3*2)) = 64g^6)

So, the expression becomes 16g^5 * 64g^6.

Next, multiply the coefficients (numbers) and add the exponents (since we are multiplying terms with the same base, we add the exponents according to the rule a^m * a^n = a^(m+n)).

16 * 64 = 1024

5 + 6 = 11

So, the simplified expression is 1024g^11.

This problem has been solved

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