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6(4+2r)=3(5r+3)

Question

6(4+2r)=3(5r+3)

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Solution

Sure, let's solve the equation step by step:

  1. First, distribute the numbers outside the parentheses on both sides of the equation:

    64 + 62r = 35r + 33 24 + 12r = 15r + 9

  2. Then, rearrange the equation to get all terms involving r on one side and the constant terms on the other side:

    12r - 15r = 9 - 24 -3r = -15

  3. Finally, solve for r by dividing both sides of the equation by -3:

    r = -15 / -3 r = 5

So, the solution to the equation 6(4+2r)=3(5r+3) is r = 5.

This problem has been solved

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