A photon of light enters a block of glass after travelling through a vacuum. The energy of the photon on entering the glass blockIncreases because its associated wavelength decreasesDecreases because the speed of the radiation decreasesStays the same because the speed of the radiation and the associated wavelength do not changeStays the same because the frequency of the radiation does not change
Question
A photon of light enters a block of glass after travelling through a vacuum. The energy of the photon on entering the glass blockIncreases because its associated wavelength decreasesDecreases because the speed of the radiation decreasesStays the same because the speed of the radiation and the associated wavelength do not changeStays the same because the frequency of the radiation does not change
Solution
The energy of a photon of light stays the same when it enters a block of glass after travelling through a vacuum. This is because the frequency of the radiation does not change.
Here's a step-by-step explanation:
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A photon's energy is determined by its frequency, according to the equation E=hf, where E is energy, h is Planck's constant, and f is frequency.
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When a photon enters a different medium, such as from a vacuum into glass, its speed and wavelength change. However, its frequency remains constant.
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Since the frequency remains constant and the energy of the photon is directly proportional to its frequency, the energy of the photon remains the same.
So, the correct answer is "Stays the same because the frequency of the radiation does not change".
Similar Questions
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