To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
- N is the final amount of the substance
- N0 is the initial amount of the substance
- t is the time that has passed
- T is the half-life of the substance

In this case, we want to find N/N0, which is the fraction of the substance that remains after time t. We know that t = 7571.03 years and T = 1600 years. Plugging these values into the formula gives us:

N/N0 = (1/2)^(7571.03/1600)

Calculating this gives us approximately 0.0064, or 0.64% when expressed as a percentage. Therefore, about 0.64% of the radium-226 would be left after 7571.03 years.

Question

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
- N is the final amount of the substance
- N0 is the initial amount of the substance
- t is the time that has passed
- T is the half-life of the substance

In this case, we want to find N/N0, which is the fraction of the substance that remains after time t. We know that t = 7571.03 years and T = 1600 years. Plugging these values into the formula gives us:

N/N0 = (1/2)^(7571.03/1600)

Calculating this gives us approximately 0.0064, or 0.64% when expressed as a percentage. Therefore, about 0.64% of the radium-226 would be left after 7571.03 years.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
- N is the final amount of the substance
- N0 is the initial amount of the substance
- t is the time that has passed
- T is the half-life of the substance

In this case, we want to find N/N0, which is the fraction of the substance that remains after time t. We know that t = 7571.03 years and T = 1600 years. Plugging these values into the formula gives us:

N/N0 = (1/2)^(7571.03/1600)

Calculating this gives us approximately 0.0064, or 0.64% when expressed as a percentage. Therefore, about 0.64% of the radium-226 would be left after 7571.03 years.

Radium-226 is radioactive and has a half life of 1600. years. What percentage of a sample would be left after ×7.57103 years?Round your answer to 2 significant digits.

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